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3 years ago

Find the indicated term 31st term: 12, 7, 2, -3

Mathematics

1 answer:

melomori [17]3 years ago

6 0

The nth term rule is -5n + 17.
So you have to do -5 multiplied by 31 + 17.
The answer= -138

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When it is 6:00 a.m. in Honolulu, it is 3:00 p.m. in London. Just before Paul’s flight from Honolulu to London, he called his fr

sineoko [7]

Answer:

b. winter wear, appropriate for around 20-45°F

Step-by-step explanation:

When it is 6:00 hours in Honolulu, it is 15:00 hours in London, this means that there are 15 - 6 = 9 hours of difference.

Paul got into London at 12:00 p.m, that is, at 12 - 9 = 3:00 p.m. Friday Honolulu time. Paul’s flight left Honolulu at 2:00 p.m. Thursday, so he spent 25 hours flighting.

When the flight started, the temperature in London was 30 °C, after 25 hours the temperature dropped 25 °C, so it was 30 - 25 = 5 °C.

To convert from °C to °F, we use the following formula:

(x °C × 9/5) + 32 = y °F

Replacing with x = 5

(5 °C × 9/5) + 32 = 41 °F

6 0

3 years ago

Read 2 more answers

hakeem's frog made 3 quick jumps. the first was 1m. the second was 85cm and the third was 400mm. what was the total length in cm

azamat

1m=100cm
85 cm
400 mm=40 cm
Add up them up and you get 225 cm in total

4 0

3 years ago

What are the possible values of x in 32x + 20 = 28x − 16x2?

maw [93]

Answer:

B .`-(1)/(8) stackrel(+)(-) (isqrt(79))/(8)`

8 0

3 years ago

Insert geometric means in each geometric sequence.

Digiron [165]

Answer:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the $n^{th}$ term of a geometric sequence.

$a_n=ar^{n-1}$

Where $a$ is the first term and

$r$ is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

$ar = 24\\ar^4 = \dfrac{3}{64}$

Solving the above equation:

$r = \dfrac{1}{8}$

Therefore, the sequence is:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

Considering the second given sequence:

$ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2$

Therefore, the sequence is:

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

Considering the third sequence:

$a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3$

Therefore, the sequence is:

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

5 0

3 years ago

What is the solution of a - 1 > 11

ozzi

A>12!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

8 0

3 years ago