When you simplify the expression you get 38. Hope this helps.
Answer = 38.
To solve for <em>x</em>, we must first isolate the term containing <em>x</em> which in this problem is 5x.
Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.
On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.
Now we can finish things off by just dividing both sides of the equation by 5. On the left the 5's cancel and on the right, 10 divided by 5 is 2 so <em>x = 2</em>.
Answer:
x=26
Step-by-step explanation:
The picture will explain.
1.
a)Two different methods for ordering these wrenches are either
converting the measurements into decimal or converting them into
fractions.
b) I chose to convert them into fractions with an LCD of 16. The fractions
are: 8/16, 12/16, 6/16, 10/16, 5/16, 7/16, 11/16
c) The ordered form of the fractions, from least to greatest, is 5/16, 3/8,
7/16, 1/2, 5/8, 11/16, 3/4
2. I don't see how I can put them on a number line.
3. The number line can definitely be used to support the answer from part C (if it is done correctly). That is because if the order on the number line is the same as the order in C, then we know that C is correct. In addition, since the number line includes benchmarks, we can easily see if the answer to C is incorrect.
Answer:
The area of the quadrilateral B-H-G-E is 7
Step-by-step explanation:
The area of the parallelogram = 60
It can be shown that ΔG-D-F = 3/10 × Area of the parallelogram S = 3/10×S
Because the diagonal B-D shares A-F into the ratio 1:2, the ΔH-D-A = 2/3×ΔD-B_A where ΔD-B_A = 1/2·S, therefore, ΔD-B_A = 2/3×1/2×S = 1/3×S
ΔB-F-H is similar to ΔD-B_A scaled to 1/2,
Therefore;
The area of ΔB-F-H = 1/4×Area of ΔD-B_A = 1/4×1/3×S = 1/12×S,
ΔF-C-D = 1/4×S
ΔE-A-D = 1/4×S
The area of the quadrilateral B_H_G_E found as follows;
Area B_H_G_E = S - (ΔF-C-D + ΔG-D-F +ΔE-A-D +ΔB-F-H)
Area B_H_G_E = S - (1/4×S + 1/10×S +1/4×S +1/12×S) = S - 53/60×S = 7/60×S
Whereby we are given that the area, S of the parallelogram AB-CD = 60 we have;
Area B_H G_E = 7/60×60 = 7
