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mr Goodwill [35]
3 years ago
8

How many grams of CO are needed to react with 1.68 mol of Fe2O3 ?

Chemistry
1 answer:
Keith_Richards [23]3 years ago
4 0

Answer:

Iron (lll) oxide reacts with carbon monoxide according to the equation: Fe203(s) + 3 CO(g)-2Fe(s) + 3 CO2(g) A reaction mixture initially contains 22.55 g Fe203 and 14.78 g CO.

Explanation:

I hope this helps (:

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Which type of molecule is shown below?
zubka84 [21]

Answer:

\boxed{\mathrm{Alkene}}

Explanation:

The hydrocarbon shown has a double bond. Hydrocarbons with double bonds are known as alkenes.

Cyclic alkanes have cyclic structure.

Alkanes only have single bonds.

Alkynes have triple bonds.

8 0
3 years ago
Read 2 more answers
Good chemistry question
NeX [460]
Compared to the charge and mass of a proton an electron has......

A proton has approximately the same mass as..........
5 0
4 years ago
What is the name of the configuration management procedure that involves the collection of information about a system under norm
raketka [301]

The name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.

<h3>What is Baselining?</h3>

Baselining is a management process used to analyze a collection of information about a particular system.

This procedure (Baselining) is well known to analyze computer performance in a given network.

In conclusion, the name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.

Learn more about Baselining here:

brainly.com/question/25836560

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5 0
2 years ago
If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?
ss7ja [257]

Answer:

V=22.4L

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm}  \\\\V=22.4L

Best regards.

4 0
3 years ago
An unknown metal sulfate is found to be 72.07% SO4 2- by mass. Assuming that the charge on the metal cation is +3, determine the
wariber [46]
Lets name the unknown metal as M. Cation would be M³⁺.
the molecular formula of the compound is M₂(SO₄)₃
the mass of one mole - (molar mass of M x2 + 3 x molar mass of SO₄²⁻)
                                   = 2M + 96 x 3
                                   = 2M + 288
In 1 mol if there's 72.07% of sulphate , 
then 72.07 % corresponds to 288 g
               1 % is then      - 288/72.07 
       100 %  of the compound - 288/72.07 x 100 
 molar mass of the compound - 399.6 g/mol
mass of 2M - 399.6 - 288 = 111.6 g
molar mass of M - 111.6 /2 = 55.8 g/mol
the element with molar mass of 55.8 is Fe.
Unknown metal is iron(III) , Fe³⁺

8 0
3 years ago
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