Calculate the ph of a 0.25M solution of monochloroacetic acid at 25 c
1 answer:
<h3>
Answer: <em>
pH=2.25 </em></h3>
Explanation:
monochloroacetic acid also means: chloroacetic acid
pKa of monochloroacetic acid= 1.4 x 10^-3 (I believe this should have been given in the problem or perhaps in the textbook)
Formula: pH= pKa + log ( some number in M)
pH= -log (1.4 x 10^-3) + log (0.25M)= 2.85 + -0.602= 2.25
pH= 2.25
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