The volume<span> of </span>gas<span> because of the </span>increase<span> and decrease in the speed in which the molecules bounce around. ... Boyle's Law states that if temperature stays the same, the </span>amount of<span> space a </span>gas takes up will increase<span> if the </span>pressure<span> decreases. The </span>amount of gas<span> will take up less space if the </span>pressure<span> is increased. this would be the correct answer </span>
Answer:
C
Explanation:
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Answer:
42 liters of oxygen (liquid) weighs 47900 grams.
Explanation:
Answer:
The equilibrium constant in terms of concentration that is, 
.
Explanation:
The relation of 
is given by:
= Equilibrium constant in terms of partial pressure.=98.1
= Equilibrium constant in terms of concentration =?
T = temperature at which the equilibrium reaction is taking place.
R = universal gas constant
= Difference between gaseous moles on product side and reactant side=
The equilibrium constant in terms of concentration that is, .
Answer:
M.Mass = 3.66 g/mol
Data Given:
M.Mass = M = ??
Density = d = 0.1633 g/L
Temperature = T = 273.15 K (Standard)
Pressure = P = 1 atm (standard)
Solution:
Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.
P V = n R T ---- (1)
Also, we know that;
Moles = n = mass / M.Mass
Or, n = m / M
Substituting n in Eq. 1.
P V = m/M R T --- (2)
Rearranging Eq.2 i.e.
P M = m/V R T --- (3)
As,
Mass / Volume = m/V = Density = d
So, Eq. 3 can be written as,
P M = d R T
Solving for M.Mass i.e.
M = d R T / P
Putting values,
M = 0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm
M = 3.66 g/mol
