Question 23Get help answering Molecular Drawing questions Get help answering Molecular Drawing questions.A compound with molecul
ar formula C9H10O2 exhibits a triplet at δ 1.2 (3H), a quartet at δ 2.6 (2H), a doublet at δ 7.3 (2H), a doublet at δ 8.0 (2H) and a singlet at δ 11 (1H) in its 1HNMR spectrum. What is the structure for this compound?MarvinJS Response ImageEdit
1 answer:
Answer:
The structure for the compound elucidated (4-Ethylbenzoic acid) is attached below.
Explanation:
Degree of Unsaturation = (where n = no of moles)
=
= 9 - 6+1 = 4
⇒ 2 ring. 3 double bonds.
From the 1H NMR data given (peaks labeled A-E)
A. 1.2 (3H, t) ⇒ -CH3
B. 2.6 (2H, q) ⇒ -C=C-H or Aromatic-CH3
C. 7.3 (2H, d) ⇒ Aro.-H
D. 8.0 (2H, d) ⇒ Aro.-H
E. 11.0 (1H, s) ⇒ -COOH
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