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Vlad [161]
3 years ago
10

Give the name of the following molecule.

Chemistry
2 answers:
frez [133]3 years ago
8 0

Answer:

This molecule is known as Tetrahydrogen dicarbon molecule

Explanation:

Korvikt [17]3 years ago
5 0
It is

6-methyl oct-2-ene
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What particles in an atom are involved in nuclear reactions
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Explanation:

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What characterizes a homogeneous mixture?
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Which is the best volumetric glassware to use for accurately measuring a set volume of liquid?
AlekseyPX

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3 years ago
Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.
algol13

Answer : The value of \Delta G_{rxn} is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.1)^3}{(1.4)^2}

Q=3.375

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -28.0 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)

\Delta G_{rxn}=-24.9kJ/mol

Therefore, the value of \Delta G_{rxn} is -24.9 kJ/mol

5 0
3 years ago
Can pH be less than zero???
k0ka [10]

Answer:

No.

Explanation:

It can be from 1 to 14.

8 0
3 years ago
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