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bonufazy [111]
3 years ago
5

Solve 105% as a fraction.

Mathematics
2 answers:
hram777 [196]3 years ago
7 0

Answer:

21/20

Step-by-step explanation:

105% as a fraction is 105/100 which can be simplified to 21/20

Nitella [24]3 years ago
4 0

Answer:

21/20

Step-by-step explanation:

Step 1: We represent the given number in percentage as a fraction by dividing it by 100. Hence, 105% is written as 105/100.

Step 2: Simplify the fraction by using common factors of numerator and denominator.

On Simplifying the resultant fraction, we get

105% = 105/100 = 21/20 [Dividing numerator and denominator by their greatest common factor that is 5]

Therefore, 105% can be represented as 21/20 in 

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Line segment A B is longer than Line segment F D. This is the correct statement from the given statements.

Step-by-step explanation:

Given:

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∠BCA = 72° and ∠DEF = 65°

Now by the property of a Triangle we know that

Side opposite to the greater angle is longer than the side opposite to the smaller angle.

So, Side opposite to the greater angle (∠BCA = 72°) is AB and

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Therefore, side AB is Longer than side FD.  

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3 years ago
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6 0
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A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

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The answer to your question is 67
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