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3 years ago

Solve 105% as a fraction.

Mathematics

2 answers:

hram777 [196]3 years ago

7 0

Answer:

21/20

Step-by-step explanation:

105% as a fraction is 105/100 which can be simplified to 21/20

Nitella [24]3 years ago

4 0

Answer:

21/20

Step-by-step explanation:

Step 1: We represent the given number in percentage as a fraction by dividing it by 100. Hence, 105% is written as 105/100.

Step 2: Simplify the fraction by using common factors of numerator and denominator.

On Simplifying the resultant fraction, we get

105% = 105/100 = 21/20 [Dividing numerator and denominator by their greatest common factor that is 5]

Therefore, 105% can be represented as 21/20 in

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3 years ago

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andreyandreev [35.5K]

Answer:

Step-by-step explanation:

The sum of years method is used to calculate the depreciation of an asset. Depreciation is the decrease value of an asset, because it's assumed that its value decreases over time.

We need to calculate a Depreciation Base or Depreciable Cost, and Depreciation Fraction, as the formula attached indicates.

First, the Depreciation Base is calculated by subtracting the total amount $12,000 with the salvage value $3,000 which results in $9,000.

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Second, we know that the Remaining Useful Life of the Asset is 5 years, and the sum of the years digits is 1 + 2 + 3 + 4 + 5 = 15, which give us 5/15 as Depreciation Fraction. Then, we are able to calculate the Depreciation Expense.

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3 years ago

Find T, N, and kappa for the plane curve Bold r left parenthesis t right parenthesis equalsleft parenthesis 7 Bold cos t plus

pickupchik [31]

Answer:

Step-by-step explanation:

r(t) = (7 cost + 7t sin t)i + (7 sin t - 7t cos t)j

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$=(7(-\sin t)+7(1* \sin t+t \cos t))i+(7 \cost -7(1*\cos t - t \sin t))j\\\\=7((-\sin t+\sin t+t \cos t)i+(\cos t-\cos t+t \sin t)j)\\\\=7((t\cos t)i+(t\sin t)j)$

$\bar r'(t)=\frac{d \bar r t}{dt} =(7t\cos t)i+(7t\sin t)j---(1)\\\\11\bar r(t)=\sqrt{(7t\cos t)^2+(7t\sin t)^2}\\\\=\sqrt{49t^2(\cos^2t+\sin^2 t)} \\\\=7t$

$\bar T (t)=\frac{\bar r'(t)}{11\bar r(t)11} =\frac{(7t\cos t)i+(7t\sin t)j}{7t} \\\\\barT(t)=(\cos t)i+(\sin t)j$

$\bar T'(t)=\frac{d}{dt} (\cos t)i+\frac{d}{dt} (\sin t) j\\\\\bar T'(t)=(-\sin t)i+(\cos t)j---(2)\\\\11\bar T'(t)=\sqrt{(-\sin t)^2+(\cos t)^2} \\\\=\sqrt{\sin^2t+\cos^2t} \\\\=1$

$\bar N(t)=\bar T'(t)=\frac{(-\sin t)i+(\cos t)j}{(1)} \\\\ \large \boxed {\bar N(t)=(-\sin t)i+(\cos t)j}$

$K(t)=\frac{|\b\r T'(t)|}{\bar r (t)|} \\\\=\frac{|-\sin t i+\cos t j|}{|7t\cos t +7t \sin t j|}$

Using eq (1) and (2)

$K(t)=\frac{\sqrt{(-\sin t)^2+(\cos t)^2} }{\sqrt{(7t\cos t)^2+(7t\sin t)^2} }\\\\=\frac{\sqrt{\sin^2 t+\cos^2t} }{\sqrt{49t^2(\cos^2 t+\sin^2t)} }\\\\=\frac{\sqrt{1} }{\sqrt{49t^2\times 1} } \\\\ \large \boxed {K(t)=\frac{1}{7t} }$

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