9514 1404 393
Answer:
x = -4/3y² -40/3y -103/3
x = -4/3(y +5)² -1
Step-by-step explanation:
Solve for x.
x = (4y² +40y +103)/(-3)
x = -4/3y² -40/3y -103/3 . . . . 'standard form' in the US
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Taking our clues from the graph*, we can write the vertex form equation as ...
x = -4/3(y +5)² -1 . . . . . . 'standard form' in other places
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* The vertex is (-1, -5), so for some leading coefficient, the equation will be ...
x = a(y -(-5))² +(-1) = a(y +5)² -1
The value of 'a' is the scale factor. Here, that is the difference between the parabola value (x = -2 1/3) and the vertex value (x = -1) one unit away from the vertex.
Option 1.
sin(2x) = 2sin(x)cos(x)
cos(2x) = 1 - 2sin(x)^2
Answer: help me on my question
Step-by-step explanation:write the answer then submit it and thanks tou
Answer:
14, 19, 26, 7
Step-by-step explanation:
f(3) = 2(3)^2 - 3(3) + 5
f(3) = 2(9) - 9 + 5
f(3) = 18-9+5
f(3) = 14
f(-2) = 2(-2)^2 - 3(-2) + 5
f(-2) = 2(4) + 6 + 5
f(-2) = 8 + 6 + 5
f(-2) = 19
g(10) = 3(10) - 4
g(10) = 30-4
g(10) = 26
17 = 3x-4
21 = 3x
7 = x
F is odd if and only f f(-x) = -f(x) so f(x) = 0 works because 0 = 0 always.
f is even if and only if f(-x) = f(x) so f(x) = 0 works because there's no x term so nothing changes. 0 = 0.