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Licemer1 [7]
3 years ago
5

Complete the square to solve the equation below check all that apply x^2+8x-2=18

Mathematics
2 answers:
vlada-n [284]3 years ago
6 0

x^2+8x-2=18

x^2+8x-2-18= 18-18

x^2+8x-20= 0

(x-2)(x+10)=0

x-2= 0 , x+10=0

x-2+2= 0+2, x+10-10= 0-10

x=2 , x=-10

Answers are x= 2 -B, x=-10 -A.

padilas [110]3 years ago
5 0

Answer:

Option A and B

Step-by-step explanation:

Given : Quadratic equation x^2+8x-2=18

To find : Complete the square to solve the equation below check all that apply ?

Solution :

Re-write, x^2+8x-2=18

x^2+8x-20=0

Applying quadratic formula,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=1 , b=8, c=-20

x=\frac{-8\pm\sqrt{8^2-4(1)(-20)}}{2(1)}

x=\frac{-8\pm\sqrt{64+80}}{2}

x=\frac{-8\pm\sqrt{144}}{2}

x=\frac{-8\pm12}{2}

x=-4\pm6

x=-4+6,-4-6

x=2,-10

The solution of the equation is x=2,-10.

Therefore, Option A,B satisfy the equation.

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Line Equation from Two Points
Verdich [7]

Hi!

We can use <u>point-slope form </u>to solve this.

y-y_{1} =m(x -x_{1})

y_{1}<em> and </em>x_{1}<em> will be from one of the points.</em>

<u>First, we have to find </u>m<u>, the slope. We can use the slope equation to get this.</u>

\frac{y_{1} -y_{2} }{x_{1} -x_{2} }

<em>Plug in your points:</em>

\frac{4-0}{8-(-8)} =\frac{4-0}{8+8} =\frac{4}{16} =\frac{1}{4}

Your slope is \frac{1}{4}

<u><em>Now plug points and slope into point-slope equation. We will use (8, 4).</em></u>

y-4=\frac{1}{4} (x-8)

Now, if you want to get it into y = mx + b form, you have to solve for y:

y-4=\frac{1}{4} (x-8)

y-4=\frac{1}{4} x-2

y=\frac{1}{4} +2

Your equation is y=\frac{1}{4} +2

<u><em>For more information on how to get the equation of a line when given two points, see here:</em></u>

brainly.com/question/986503

7 0
2 years ago
Two bicyclists are 7/8 of the way through a mile long tunnel when a train approaches the closer end at 40 mph. The riders take o
Anastaziya [24]

Answer:

the cyclists rode at 35 mph

Step-by-step explanation:

Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then

distance= speed*time

since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :

time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train

thus denoting v as the speed of the cyclists :

7/8*L / v = L / 40 mph

v = 7/8 * 40 mph = 35 mph

v= 35 mph

thus the cyclists rode at 35 mph

6 0
4 years ago
Write an equation for the description.<br> Two-thirds a number x plus 4 is 6.
antiseptic1488 [7]
2/3x + 4=6. Is that what you mean?
8 0
3 years ago
Hey I need help with this question:<br><br> 6(x-3)^2-26 = 10
ra1l [238]

Answer:

x = 3 ±sqrt(6)

Step-by-step explanation:

6(x-3)^2-26 = 10

Add 26 to each side

6(x-3)^2-26+26 = 10+26

6(x-3)^2 = 36

Divide by 6

6/6(x-3)^2 = 36/6

(x-3)^2 = 6

Take the square root of each side

sqrt((x-3)^2) = ±sqrt(6)

x-3 =  ±sqrt(6)

Add 3 to each side

x-3+3 =3 ±sqrt(6)

x = 3 ±sqrt(6)

7 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
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