This puzzle is relatively easy, I just posted here cause I wanted to see if how many people can solve it. I capitalized some of
1 answer:
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We evaluate b^2 - 4ac. If the answer is positive, then there are two real solutions. If it is zero, there is one real solution. If it is negative, there are 2 complex solutions. In this equation, a = 1, b = 5, c = 7. Now we plug in the numbers.
Because this answer is positive, there are two real solutions.
Because this answer is positive, there are two real solutions.