The question is telling you that the length of the rectangle is 3 metres more than twice the width.
So let:
<em>w= width</em>
<em>L= length</em>
Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>
They also tell you the perimeter is 48 metres.
<em>P= L+L+w+w</em>
So the equation of the perimeter is:
<em>48= (2w+3)+(2w+3)+2w +2w</em>
<em>48= 2(2w+3) + 4w</em>
To find w, expand and simplify.
<em>48= 4w+6+4w</em>
<em>48= 8w + 6</em>
<em>42= 8w</em>
<em>5.25=w</em>
Now that you know the width, plug in the value into the length equation:
<em>L= 2w+3</em>
<em>L=2(5.25)+3</em>
<em>L=10.50+3</em>
<em>L=13.5</em>
If I am wrong let me know! I hope this helps.
Answer:
Step-by-step explanation:
To copy an angle we follow the following steps,
1). Draw a working line with the help of a straightedge.
2). Now we put a point S as the vertex of the angle.
3). Construct an arc with a radius 'r' (any length ) from vertex S which intersects the working line say at V.
4). With the same radius we draw an arc from point E which intersects the line ED and EF at G and H respectively.
5). Mark an arc from point G which intersects line EF at I.
6). Measure the distance between points G and I with compass and mark an arc from point V which intersects the previous arc say at U.
7). Now join the points S and U.
Hence we copy any angle.
I don’t really know exactly what you’re asking but if you’re asking what is most practical, it would be #4
A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances or phases. The three phases or states of matter are gas, liquid, and solid.
