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nika2105 [10]
2 years ago
11

Hi plz answer this I'll give u more points if u do

Mathematics
1 answer:
Brrunno [24]2 years ago
6 0

Answer:

6 feet in the distance

Step-by-step explanation:

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Which expression is equivalent to 173/22
Advocard [28]

Answer:

7.863

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the HCF of ; 3.36,60,84​
dolphi86 [110]

Answer:

3

Step-by-step explanation:

im guessing 3.36 is a typo and it should be 3,36,60,84

so in that case it would be 3

5 0
3 years ago
Read 2 more answers
Really need help with this equation someone please solve much appreciated
Charra [1.4K]

Answer:

16,500 m

Step-by-step explanation:

The volume formula for a pyramid such as this is:

Volume = 1/3 x area of base x height

First let's find the area of the base (which in this example is a rectangle)

Our base dimensions are 60 m x 15 m

60 x 15 = 900

Our height is 55 m.

V = 1/3 x 900 x 55

Multiply the 900 by 1/3 first (or divide it by 3)

V = 300 x 55

V = 16,500 m

Our final answer is 16,500 m.

5 0
3 years ago
17
wlad13 [49]

Answer:

Mean: 17.18

Median: 16

Mode: none/all numbers in the data

Range: 46

Step-by-step explanation:

7 0
3 years ago
Given: R=2m <br> KL = LM = KM<br> Find: V and<br> Surface Area of the cone
lilavasa [31]

Answer:

The volume of the cone is 3π≈9.42.

The surface area of the cone is 9π≈28.27.

Step-by-step explanation:

If we make a section of the sphere and the cone, we have a equilateral triangle inscribed in a circle (see picture attached).

We only know the numerical value of the radius R, that is 2 m.

From the picture, we have

\bar{KM}=2\cdot R\cdot cos(30^{\circ})=2R\dfrac{\sqrt{3}}{2}=\sqrt{3}R= 2\sqrt{3}

The radius of the base of the cone is

r=\bar{KO}=\bar {KM}/2=(2\sqrt{3})/2=\sqrt{3}

The height of the cone can be calculated as:

h=\bar{LO}=\bar{KL}\cdot cos(30^{\circ})=(2\sqrt{3})*(\sqrt{3}/2})=3

The volume of the cone can be calculated as:

V=\dfrac{1}{3}\pi r^2h=\dfrac{1}{3}\pi (\sqrt{3})^2*3=3\pi\approx9.42

The surface area of the cone is:

S=S_{base}+S_{face}=\pi r^2+\pi r l=\pi r^2+\pi r (\bar{KL})\\\\S=\pi(\sqrt{3})^2+\pi \sqrt{3}*2\sqrt{3}=3\pi+2\pi*3=(3+6)\pi=9\pi\approx 28.27

4 0
3 years ago
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