A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
Answer:
2.83
Step-by-step explanation:
F=9/5C+32
rewrite as 9/5C+32=F
9/5C+32-32=F-32
9/5C=F-32
(5*9/5)C=(F-32)*5
9C=5F-160
9/9C=(5F-160)/9
C=(5F-160)/9
Answer:
99.38
Step-by-step explanation:
the area of all the circles by using the formula A=ℼr2 then filling in r with 3.2 A=ℼ3.22=32.2
Knowing that one circle is 32.2 4 circles would have an area of 128.8
Two circles have a combined length and height of 12.8 because the circumference of one circle is 6.4 so two circles reach the sides of the square. So all the sides of the square are 12.8. So finding the area of the square knowing what the sides are, so the area is a=163.84. To find the shaded area you subtract the volume of the square to volume of all 4 circles which is 163.84-128.8 which equals 35.04. Then you find the volume of the semi circle which is 64.34. Then the combination of both shaded regions is 99.38
d - 3 = (-8)
+3 +3
d = -5
⭐ Please consider brainliest! ⭐
✉️ If any further questions, inbox me! ✉️
