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Artist 52 [7]
3 years ago
14

If x = 3.5: (4x - 2)/10

Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

its 1.2

Step-by-step explanation:

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horsena [70]
Need to know the radius.
7 0
3 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
Naiomis fish is 40 mm long her guinea pigis 25cm long
dimaraw [331]

Answer:

1,000

Step-by-step explanation:

If your asking for the area you multiply 40 times 25

6 0
3 years ago
15 × (-3) × n = 908989
Juliette [100K]
Ggggggyrftgtgggfcxfdfftytyyggyyy
5 0
3 years ago
Anna has leaned a ladder against the side of her house. If the ladder forms a 72º angle with the ground and rests against the ho
LuckyWell [14K]

Answer:

(A) 2 meter

Step-by-step explanation:

It is given that the ladder forms a 72º angle with the ground and rests against the house at a spot that is 6 meters high.

Let the measure of bottom of the ladder from the wall be x, then using the trigonometry, we have

\frac{CB}{AB}=tan72^{\circ}

\frac{6}{x}=tan72^{\circ}

\frac{6}{x}=3.077

x=\frac{6}{3.077}

x=1.94

x≈2m

Thus, option A is correct.

6 0
3 years ago
Read 2 more answers
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