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Savatey [412]
3 years ago
5

How to do 4x=3y-7 and x=4

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
4x=3y-7
4(4)=3y-7
16=3y-7
+7      +7
23=3y
      divide by 3 on both sides 
7.6 or 7.7 rounded = y
You might be interested in
Which expression is equivalent to n2 + 26n + 88 for all values of n?
Lelechka [254]

Answer:

Option B is correct.

The expression which is equivalent to  n^2+26n+88  is; (n+22)(n+4)

Explanation:

Given the equation: n^2+26n+88 for all values of n.

The quadratic equation in this form; ax^2+bx+c =0

First find two numbers that multiply to give ac and add to give b.

From the given equation;

a =1 , b = 26 and c =88

then,

the two number that multiply to give ac =88 is, 22 or 4

and they add up to give b=26 (i.e 22+4)

Now, rewrite the middle term i.e 26n with 22n and 4n , we have

n^2+22n+4n+88=0

Now, factor the first two terms and last two terms,

n(n+22)+4(n+22)

we see that (n+22) is common to both terms so, we have;

(n+22)(n+4)

Therefore, the expression (n+22)(n+4) is equivalent to  n^2+26n+88

Check:

(n+4)(n+22) = n\cdot n+ 22n+4n+88=n^2+26n+88   [ True]



5 0
3 years ago
Read 2 more answers
Part A. Write an equation that misled the linear relation in the graph.
irakobra [83]
Part A. y = -3x - 2

Part B. = y = -3x - 11

Hope this helps!!
~Kiwi
5 0
4 years ago
A carpenter is building a rectangular room with a fixed perimeter of 440 ft. what are the dimensions of the largest room that ca
olga55 [171]
The biggest it can be is 110 by 110, and the area would be 2,100 ft.

Hope this helps!
4 0
3 years ago
The prime factorization of 180X²Y? (PLEASE HELP)
Law Incorporation [45]
Answer:Use a calculator

Explanation:it’s easier
8 0
3 years ago
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
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