Multiplication all you have to.do is multiply the denominators.
What we want to draw is the half closed interval:
I= [-5, 4) excluding 0,
as the union of 2 different intervals say a and b.
Let a be the interval containing the smallest value.
Then the smallest value of a is -5, and the largest possible value of a is 0, not included, if we want to write a as an interval, without "gaps", or "holes".
So a=[-5, 0)
similarly, b=(0, 4).
Answer: [-5, 4)=[-5, 0)∪(0, 4)
I don’t know sorry! I might learn that soon so… I’ll see if u can help lately
It's given in the question,
P, Q, V and K are collinear.
VP = 14x + 4
PK = x + 630
VQ = 17x + 6
KQ = 11x + 5
By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = 
x = 15
Therefore, value of VP = (14x + 4)
= 14(15) + 4
= 214 units
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Answer: OPTION D.
Step-by-step explanation:
The formula for calculate the circumference of a circle is:

Where <em>r</em> is the radius.
The formula for calculate the area of a circle is:

Where <em>r</em> is the radius.
Solve for <em>r</em> from
to calculate it:

Subsitute the radius into
. Then:
