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3 years ago

Warm up question, what is 5/6 + 5/6? Explain how you got the answer.

Mathematics

2 answers:

Helga [31]3 years ago

6 0

Answer: 5/3

Step-by-step explanation:

Vladimir [108]3 years ago

3 0

Answer:

1 2/3??

Step-by-step explanation:

just a guess i.d.k :>

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Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n?

Oxana [17]

Answer:

The answer is All integers where n ≥ 1

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3 years ago

AAAAAAAAAAA 65 points please help

nata0808 [166]

Answer:

The distance between E and F is 5 units

Step-by-step explanation:

E and F are share the same y-coordinates. So for this part it is okay to not use the distance formula. 

So you will be having:

E (5,8) and F (5,3)

EF = 8-3=5

OR 

YOU CAN USE THE DISTANCE FORMULA AS INDICAYED IN THE PICTURE.

Hopefully the picture is clear and understandable and younger the explanation.

4 0

2 years ago

Help Please! I will mark you as brainlyest!!!

frez [133]

Yo bro bro I’m bout to get my food now

5 0

2 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers

PLEASE HELP AND EXPLAIN SO I CAN LEARN. THANKS. Indicate whether each item described contains parallel lines or perpendicular li

AfilCa [17]

Answer:

Hey! I think I can help.

Parallel lines are lines that can't meet.Perpendicular lines are lines that can meet.

e.)Since the line at 12 and the line at 9 meets then it is a perpendicular line.

c.)Perpendicular line.

a.)Perpendicular line.

b.)Parallel line.

d.)Depending on how they are faced if the ends of the telephone wire meets the second one then it is perpendicular but if not then it is parallel that's if they are in different directions which they can not meet.Thank you for the question

5 0

3 years ago