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iVinArrow [24]
3 years ago
10

Which is a correct first step in solving 5 - 2x < 8x - 3?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
4 0

Answer:

5< 10x -3

add like terms first

make sure X's are on one side and numbers on the other

Trava [24]3 years ago
4 0

Answer:

5  < 10x - 3

Step-by-step explanation:

5 - 2x < 8x - 3?

Add 2x to each side

5 - 2x+2x < 8x - 3+2x

5  < 10x - 3

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What is two over twelve + four over nine
noname [10]

Answer:

2/3

Step-by-step explanation:

2/12+4/9

Find a common denominator

16/72+ 32/72

48/72

Simplify

=2/3

Hope this helps

3 0
3 years ago
A four sided figure with 90° angles and two sets of opposite sides that are parallel and congruent is called a _________________
kotegsom [21]

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8 0
3 years ago
A person who weighs 100 pounds on earth weighs 16.6 lb on the moon. What is the independent variable? Explain why
Leviafan [203]
Independent variable (IV): something the scientist can change.

Thus, in this case, the IV can be the weight of the person.
5 0
3 years ago
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
If xt = 3y -1 and us = 28, find the value of y
olga55 [171]
3y - 1 = 28
+ 1 + 1
----------------
3y = 29
---- ----
3 3
y= 9.66
8 0
3 years ago
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