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3 years ago

Need help please will mark brainliest

Mathematics

1 answer:

Luda [366]3 years ago

6 0

Step-by-step explanation:

Maximum = 62

Median = (34+37+39+32+48+45+53+62+58+61+60+41)/12= 47.5≈48

quartile

In increasing order

32, 34, 37, 39, 41, 45, 48, 53, 58, 60, 61, 62

Upper quartile= (58+60)/2 = 59

Lower quartile= (37+39)/2 = 38

Minimum= 32

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Assume that y varies directly with x. If y = -5 when

steposvetlana [31]

Answer:

Thus, the value of x = -36 when y = 15

Step-by-step explanation:

We know that if y varies directly with x, we can express the relationship such as

y ∝ x

y = kx

k = y/x

where 'k' is called constant of variation.

Given

y = -5

x = 12

Using the equation

k = y/x = -5/12

Thus, the value of k = -5/12

Finding x when y = 15

y = 15

k = -5/12

substituting y = 15 and k = -5/12 in the equation

y = kx

15 = -5/12 (x)

15×12 = -5x

180 = -5x

divding both sides by -5

-5x/-5 = 180/-5

x = -36

Thus, the value of x = -36 when y = 15

8 0

3 years ago

Mrs. Smith's class is working on a variety of science experiments. Each

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

If there are n students, then the number of pairs is $\frac{n(n-1)}{2}$ .

With 12 students, $\frac{12(12-1)}{2} = \frac{132}{2}=66$ pairs can be formed.

The reason the formula works is this: Each of the 12 students can be paired with 11 other students (no student is paired with him/her self). But counting 12 x 11 = 132 counts each pair twice. Example: student A can be paired with student B,..., student B can be paired with student A. The pair was counted two times.

See the attached image that shows pairings of 5 students. There are

5(5 - 1)/2 = 5(4)/2 = 10 pairs.

8 0

3 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

P(0) = 0 and P(50) = 1,500,000

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The integrating factor is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

4 years ago

a country will produce 3000 missels this year. each of the short range missles costs $200,000 to produce. Each of the medium ran

guapka [62]

Answer:

Step-by-step explanation:

3000/10=300 300=10% of total missiles

300*3=900(30%) That country (assuming it is Iran) would produce 900 short missiles and 900 medium missiles. 3000-900(2)=3000-1800=1200.

Iran will produce 1200 long range missiles.

For the cost of the missiles,

200,000*900=180,000,000. 300,000*900=270,000,000.

870M-(180M+270M)=870M-450M=420M

420,000,000/1200=350,000.

Long Range Missiles are $350,000 each... got me thinkin bout buying some...

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3 years ago

Hey guys i just joined how do i do this

Sergeeva-Olga [200]

Answer: you can ask questions your struggling with and people like me will help you answer them. You can also help other people answer their questions and get points for it

Step-by-step explanation:

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3 years ago

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