Answer:
a 0.5
b 0.4831
c 0.4354 < P < 0.53008
Step-by-step explanation:
Given that :
Probability (P) of a head or a tail when a coin is being tossed or flipped = 1/2 = 0.5
Sample size (n) = 296
Selected sample (X) = 143
a) Given that Emily used a coin toss to select either her right hand or her left hand, what proportion of correct responses would be expected if the touch therapists made random guesses?
The proportion of correct responses that would be expected if the touch therapists made random guesses is 0.5
b) Using Emily's sample results, what is the best point estimate of the therapists' success rate?
Point estimate 
= 
= 0.4831
c) Using Emily's sample results, construct a 90% confidence interval estimate of the proportion of correct responses made by touch therapists.
The 
for 90% is 1.645
Using the formula P" -E < P < P" + E
where E = margin of error : 
= 0.0477
∴ P" -E < P < P" + E
= 0.4831 - 0.0477 < P < 0.4831 + 0.0477
= 0.4354 < P < 0.53008
The probability distribution of normal distribution is given by,
f(x) =
Where a = mean = 16 and α = standard deviation = 3
In normal distribution, skewness is zero. That is, distribution is symmetric.
Therefore, mean, median and mode coincide at a point in case of normal distribution.
50th percentile is same as median or mean or mode
Therefore, 50th percentile = 16
d i believe so it might be d if not i’m sorry
Answer:
the height is 18cm
Explanation:
If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles shown are similar, compare their corresponding sides. Are these ratios equal?
given that
Triangle 1 (first triangle)
base = 10cm
height = 15cm
Triangle 2 (second triangle)
base = 12cm
height = unknown
base 1 / base 2 = height 1 / height 2
10cm / 12cm = 15cm / xcm
xcm = 18cm
height = 18cm
The sum of length and width is half the perimeter, so that sum is 26 inches.
If length and width were equal, they would both be 26/2 = 13 inches. Adding 2 inches to one dimension and subtracting 2 inches from the other will keep the sum the same and make them differ by 4 inches.
The length and width are 15 inches and 11 inches, respectively.
