Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
Answer:
F. 8
Step-by-step explanation:
The ratio of the long side to the short side is the same in similar triangles. The long side of triangle BAD is AD, which has length 20-4 = 16.
BD/DE = AD/BD
h/4 = 16/h
h^2 = 64 . . . . . . . multiply by 4h
h = 8 . . . . . . . . . . take the square root (matches selection F)
_____
<em>Comment on this geometry</em>
BD = √(AD·DC) is called the "geometric mean" of the segments AD and DC. This geometry has some other geometric mean relationships as well:
BC = √(AC·DC)
BA = √(AC·AD)
Hello!
Since the function has no undefined points or domain constants the answer is all real numbers
The answer is all real numbers
Hope this helps!
We are asked to express cos^ 3 x in terms of powers of trigonometric functions not greater than 1
cos ^ 3 x is equal to cos x * cos^2 x.
<span>cos^2 x = 1 - sin^2 x.
</span>sin^2 x = (1 - cos 2x) /2
the answer is cos ^ 3 x = cos x * (1 - <span> (1 - cos 2x) /2 )</span>
Answer:
m-2
Step-by-step explanation:
m is being subrtacted by 2
