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jenyasd209 [6]
3 years ago
6

Solve the proportion for x.

Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0
The answer for the question is x=1
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The function of f(x) varies directly with x, and f(x)=48 when x=8.<br> Evaluate f(x) when x=2
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Here's the equation for direct variation. k=y/x    [ f(x)=y]
Find k
k= 48/8=6
6=y/2
y=12
Hope this helps. 
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andre [41]

Step-by-step explanation:

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2 years ago
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madreJ [45]
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3 years ago
What is the length of a diagonal of a cube with a side length of 10 cm? 200 cm 210cm 300 cm 320cm
Scilla [17]

Answer:

The length of the diagonal of the cube = √(3 × 10²) = √300 cm

Step-by-step explanation:

* Lets revise the properties of the cube

- It has six equal faces all of them are squares

- It has 12 vertices

- The diagonal of the cube is the line joining two vertices in opposite

 faces (look to the attached figure)

- To find the length of the diagonal do that:

# Find the diagonal of the base using Pythagoras theorem

∵ The length of the side of the cube is L

∵ The base is a square

∴ The length of the diagonal d = √(L² + L²) = √(2L²)

- Now use the diagonal of the base and a side of a side face to find the

 diagonal of the cube by Pythagoras theorem

∵ d = √(2L²)

∵ The length of the side of the square = L

∴ The length of the diagonal of the cube = √[d² + L²]

∵ d² = [√(2L²)]² = 2L² ⇒ power 2 canceled the square root

∴ The length of the diagonal of the cube = √[2L² + L²] = √(3L²)

* Now lets solve the problem

∵ The length of the side of the square = 10 cm

∴ The length of the diagonal of the cube = √(3 × 10²) = √300 cm

- Note: you can find the length of the diagonal of any cube using

 this rule Diagonal = √(3L²)

7 0
3 years ago
Read 2 more answers
Could you please help me with this problem.
vlabodo [156]

<em>Answer:</em>

<h2><em>x=</em><em>6</em><em>√</em><em>2</em></h2>

<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>

<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

6 0
3 years ago
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