How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other
1 answer:
Answer:
609638400 ways
Step-by-step explanation:
For 8 men in a line: 8! = 40320
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1 2 3 4 5 6 7 8 9 ... in order to separate 2 women, there are 9 vacant places for 5 women, we have to choose 5 out of 9
C(9,5) = 9! / 5!4! = 126
Random place 5 women in the 5 chosen places: 5! = 120
Total ways: 40320 * 126 * 120 = 609638400
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