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3 years ago

1)Find the center & radius for the following

1 answer:

4 0

The general equation of circles is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center.
1. 2x^2+2y^2=72 =x^2+y^2=36 c: (0,0); r = 6
2. (x-3)^2+(y-1)^2=4 : c: (3,1); r = 2
3. (x-5)^2+(y+2)^2=49; c: (5,-2); r = 7
4. (y-4)^2+(x-10)^2=64: c: (4,10); r = 8
5.(x^2-6x+9)+(y^2+8y+16)=1: c: (3,-4); r = 1
6. x^2+12x+y^2-8y=-27 =x^2+12x + 36+y^2-8y+16=-27+36+16=25:
c( -6,4); r = 5

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3 years ago

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Yuliya22 [10]

Answer:

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Step-by-step explanation:

2x - 3y = 1 --(1)

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x = 18 - 2y --(2)

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2(18 - 2y) - 3y = 1

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Mariana [72]

Answer:

Option C

Step-by-step explanation:

From the graph attached,

Slope of the line passing through two points A and B will be,

m = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{12}{8}$

= $\frac{3}{2}$

Triangles having same ratio of Height and base (slope) will lie on the line graphed.

Option A

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$\frac{3}{2}\neq \frac{44}{21}$

Slope of the line ≠ Slope of the triangle

Therefore, triangle will not lie on the line.

Option B

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$\frac{3}{2}\neq \frac{3}{1}$

Triangle will not lie on the line.

Option C

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$\frac{3}{2}= \frac{3}{2}$

Triangle will lie on the line.

Option D

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But $\frac{3}{2}\neq \frac{2}{1}$

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3 years ago

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3 years ago

Which situation can be represented by the inequality x-56

notsponge [240]

Complete Question:

Which situation can be represented by the inequality x > 56

A. Phil's saving account balance is $56

B. Junichi's garden is wider than 56 ft.

C. Suzanna hiked for less than 56 min.

D. It was colder than 56ºF this morning.

Answer:

Option B

Step-by-step explanation:

Given

$x > 56$

Required

Represent using a real life situation

$x > 56$ implies that the value of x is greater than 56

Examining the options one after the other

a: Account balance is $56

This option shows equality

i.e.

$x = 56$

b: Garden is wider than 56 ft.

Being wider than 56 means being greater 56;

This option shows greater than

So:

$x > 56$

c. Hiked for less than 56 min.

It is evident that this option shows less than

i.e.

$x < 56$

d. Colder than 56ºF this morning.

Being colder means the temperature is less than 56

i.e.

$x < 56$

So: from the list of given options

Only option B answers the question

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3 years ago