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Bas_tet [7]
3 years ago
11

1)Find the center & radius for the following

Mathematics
1 answer:
postnew [5]3 years ago
4 0
The general equation of circles is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center. 
1. 2x^2+2y^2=72 =x^2+y^2=36  c: (0,0); r = 6
2. (x-3)^2+(y-1)^2=4 : c: (3,1); r = 2
3. (x-5)^2+(y+2)^2=49;  c: (5,-2); r = 7
4. (y-4)^2+(x-10)^2=64:  c: (4,10); r = 8
5.(x^2-6x+9)+(y^2+8y+16)=1:  c: (3,-4); r = 1
6. x^2+12x+y^2-8y=-27 =<span>x^2+12x + 36+y^2-8y+16=-27+36+16=25:
 c( -6,4); r = 5</span>
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The graph of y = x^2 -3 is translated in 4 units to the left of the graph to give the graph A
Vedmedyk [2.9K]

Answer:

a) b = 8, c = 13

b) The equation of graph B is y = -x² + 3

Step-by-step explanation:

* Let us talk about the transformation

  • If the function f(x) reflected across the x-axis, then the new  function g(x) = - f(x)
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In the given question

∵ y = x² - 3

∵ The graph is translated 4 units to the left

→ That means substitute x by x + 4 as 4th rule above

∴ y = (x + 4)² - 3

→ Solve the bracket to put it in the form of y = ax² + bx + c

∵ (x + 4)² = (x + 4)(x + 4) = (x)(x) + (x)(4) + (4)(x) + (4)(4)

∴ (x + 4)² = x² + 4x + 4x + 16

→ Add the like terms

∴ (x + 4)² = x² + 8x + 16

→ Substitute it in the y above

∴ y = x² + 8x + 16 - 3

→ Add the like terms

∴ y = x² + 8x + 13

∴ b = 8 and c = 13

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→ That means y will change to -y as 1st rule above

∴ -y = (x² - 3)

→ Multiply both sides by -1 to make y positive

∴ y = -(x² - 3)

→ Multiply the bracket by the negative sign

∴ y = -x² + 3

b) The equation of graph B is y = -x² + 3

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