x=31,y=−61
Put the equations in standard form and then use matrices to solve the system of equations.
5x+4y=1,3x−6y=2
Write the equations in matrix form.
(534−6)(xy)=(12)
Left multiply the equation by the inverse matrix of (534−6).
inverse((534−6))(534−6)(xy)=inverse((534−6))(12)
The product of a matrix and its inverse is the identity matrix.
(1001)(xy)=inverse((534−6))(12)
Multiply the matrices on the left hand side of the equal sign.
(xy)=inverse((534−6))(12)
For the 2×2 matrix (acbd), the inverse matrix is (ad−bcdad−bc−cad−bc−bad−bca), so the matrix equation can be rewritten as a matrix multiplication problem.
(xy)=(5(−6)−4×3−6−5(−6)−4×33−5(−6)−4×345(−6)−4×35)(12)
Do the arithmetic.
(xy)=(71141212−425)(12)
Multiply the matrices.
(xy)=(71+212×2141−425×2)
Do the arithmetic.
(xy)=(31−61)
Extract the matrix elements x and y.
x=31,y=−61
Answer:
28p+14q+21r
Step-by-step explanation:
7(4p + 2q + 3r)
Use distributive property
(7)(4p)+(7)(2q)+(7)(3r)
=28p+14q+21r
Assumption:
△RST is congruent to △TXY
The vertices therefore correspond as follows.
From △TXY to △RST:
T <--> R
X <--> S
Y <--> T
Hence:
TX <--> RS
TY <--> RT
XY <--> ST
Answer:
Step-by-step explanation:
This is your answer :)
Answer:
8
Step-by-step explanation:
6(6) - 20 - 32 (1/4)
36 -20 - 8
16 - 8
8.