All categories

3 years ago

Can you help me on problem 1 of Three-Dimensional Figures

Mathematics

1 answer:

svlad2 [7]3 years ago

4 0

The answer is D) isosceles and equilateral triangle

You might be interested in

Graph the system of equations on your graph paper to answer the question.

scZoUnD [109]

y=x-4
y=-x+6
---------------------
Substitute x - 4 for y in y=-x+6
x-4=-x+6
--------------------------------
Add X on each side
x-4+x=-x+6+x
2x - 4 = 6
--------------------------------------
Add 4 on each side
2x-4+4=6+4
2x = 10
------------------------------------------------
Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
================================================================
To find Y we substitute 5 for x in y=x-4
y = 5 - 4
y = 1
-----------------------------------------------------
Your answers are Y = 1 and X = 5

8 0

3 years ago

8x-6y=54 in slope intercept form please!!

NikAS [45]

Answer: y= 4/3x-9

Step-by-step explanation:

4 0

3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago

I NEED TO GET THIS DONE BEFORE THE 8TH I forgot how to do this can I get some help.

-Dominant- [34]

Answer:

Step-by-step explanation:

they want to know the high and low quiz scores... that's all

6 0

3 years ago

A car's gas tank that is 40% full contains 12 gallons of gas. Show the math you used to find the maximum capacity of the gas tan

Lisa [10]

Answer: 30 gallons

Step-by-step explanation:

So fist we add 40% and $40%. That's 80 percent of the tank which is 12 + 12 = 24. Then we figure out half of 40 percent which is 20 which means its 6 gallons. Now we add. 12+12+6 which equals our answer 30 gallons

3 0

3 years ago

Read 2 more answers