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zhenek [66]
3 years ago
14

Can you help me on problem 1 of Three-Dimensional Figures

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
The answer is D) isosceles and equilateral triangle 
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The scale on a map is 3 inches for every 6 1/4 miles. If the distance on the map is 5 1/2 inches, how far apart are the cities i
vovikov84 [41]
I think it is 34 3/8
4 0
3 years ago
I need help quickly please have clear explanation and answer written in brainly
Andrei [34K]

Answer:

ii

Step-by-step explanation:

i

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3 years ago
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Please help me simplify 9x-3(2+4x)=
denis23 [38]
solution

1) <span>Expand
</span><span>9x−6−12x

2) </span><span>Gather like terms
</span><span>(9x−12x)−6

3) </span> <span>Simplify
</span><span><span>−3x−6</span></span>
4 0
3 years ago
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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
Kedwin has $150 and wants to buy a new pair of headphones that cost $175 + 10% shipping he decides wait until the headphones guy
SOVA2 [1]

Answer:

23%

Step-by-step explanation:

175 x 0.23 = 40.25

175-40.25 = 134.75

134.75 x 10% shipping = 13.48

134.75+13.48=148.23

7 0
3 years ago
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