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zhenek [66]
2 years ago
14

Can you help me on problem 1 of Three-Dimensional Figures

Mathematics
1 answer:
svlad2 [7]2 years ago
4 0
The answer is D) isosceles and equilateral triangle 
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3(2)(-4)-2(5-7)³+10÷5(3) <br>STEP BY STEP PLEASE. Thank you!​
SCORPION-xisa [38]

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2 years ago
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Which expression is equivalent to
nirvana33 [79]

For this case, we must find an expression equivalent to:

\frac {-9x ^ {- 1} y ^ {- 9}} {- 15x ^ 5y ^ {- 3}}

By definition of power properties we have:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

Rewriting the previous expression we have:

The "-" are canceled and we take into account that:

\frac {9} {15} = \frac {3} {5}

So:

\frac {3} {5x^5 * x ^ 1 *y ^ 9* y ^ {- 3}} =

According to one of the properties of powers of the same base, we must put the same base and add the exponents:

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Answer:

\frac {3} {5x ^ 6 * y ^ 6}

Option B

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3 years ago
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12.5 of what number is 150
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Answer: 1,200


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Someone please help with this maths problem.
NemiM [27]
The answer would be 80 because you are multiplying each number by 2. You multiply 5 x 2 = 10, 10 x 2 = 20, 20 x 2 = 40, and then 40 x 2 = 80. That is how I got the answer 80!!
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