Write the equation out: (total cost: 0.35C[per carton] + 75[delivery charge]) ≤ 500. Subtract 75 on both sides and it would be: 0.35C ≤ 425. Divide 0.35 on both sides and you'll get C ≤ 1214. Therefore, the maximum # of cartons that Elvira can buy is 1214 cartons of milk.
Answer:
The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115The angles of A and B are 45 degrees. This is true because the other angle is a right angle (90 degrees) and if you are making a triangle the degrees of the sides have to = 180 to be a complete triangle. The triangle is complete, so I took 180 – 90 = 90 ÷ 2 = 45.
The angle of C is 115 because it is a supplementary angle. A supplementary angle is an angle that has two angles with a sum of 180 degrees and 180 – 65 = 115
Step-by-step explanation:
Answer:
c) 68%
Step-by-step explanation:
The empirical rule states that most of the data will be within three standard deviations in a normal distribution. The 68% of the data will be within one standard deviation, the 95% will be within two standard deviations, and 99.7% of the data will be within three standard deviations.
A normal distribution is a continuous distribution in which values around the mean are the most frequents. It can also be called a bell-shaped distribution.
Answer:
The correct corresponding part is;
≅ 
Step-by-step explanation:
The information given symbolically in the diagram are;
ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)
Segment 
is congruent to 
( ≅ )
Segment is congruent to ( ≅ )
From which, we have;
∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∠B ≅ ∠D by CPCTC
Segment 
is congruent to 
( ≅ ) by CPCTC
Segment 
bisects 
Segment bisects
Therefore, the correct option is ≅
