It's 3.2 units
hope it's helps
Answer:
Step-by-step explanation: it is C
Answer:
Step-by-step explanation:
third option I believe
The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,

p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.