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Elodia [21]
3 years ago
13

Find 4x when 3x equals 3

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

4

Step-by-step explanation:

If 3x = 3, then x = 1, so 4x = 1(4) = 4

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Does this graph have any vertical asymptotes? If so, where?
tresset_1 [31]

Answer:

There are no vertical asympotes for this rational function.

Step-by-step explanation:

For rational functions, a vertical asymptote exists for every value of the independent variable such that function become undefined, that is, such that denominator is zero. Let be the following rational function:

C(p) = \frac{25000\cdot p}{100-p}, 0\le p < 100

There is a vertical asymptote for this case:

100-p = 0

p = 100

Which is out of the interval given to the rational function. Hence, we conclude that there are no vertical asympotes for this rational function.

5 0
3 years ago
A circle has a circumference of 25.12 inches what is the diameter of the circle
BigorU [14]

Answer:

8

Step-by-step explanation:

Recall these two equations for circumference and diameter.

Circumference = 2*pi*radius

Diameter = radius*2

25.12 = 2*pi*radius

Radius = 4

Diameter = 4*2 => 8

Thus the diameter is 8

4 0
3 years ago
The graph of y=x^3 is transformed as shown below?
Anastasy [175]
Y= -2x^3 is the answer
Hope this helps!
8 0
3 years ago
Read 2 more answers
Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec
vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}

Hence, we have:

\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\  \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}

Divide the expression for the fifth term by the expression for the second term:

\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}

Substituting the value of r into any of the expression:

\begin{gathered} ar\text{ =  18} \\ a\text{ }\times\text{ 2 =  18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}

Hence, the explicit rule for the sequence is:

a_n\text{ = 9\lparen2\rparen}^{n-1}

5 0
1 year ago
Simplify the following expression. <br>7^-5/6.7^-7/6. <br>1/49<br>1/14<br>14<br>49
Serggg [28]

{7}^{  - \frac{5}{6} }  \times  {7}^{ -  \frac{7}{6} }  \\  =  {7}^{ -  \frac{5}{6} -  \frac{7}{6}  }  \\  =  {7}^{  -  \frac{12}{6} }  \\  = {7}^{ - 2}  \\  =  \frac{1}{ {7}^{2} } \\  =  \frac{1}{49}
The answer is 1/49
4 0
3 years ago
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