Answer:
A
Step-by-step explanation:
y = (-2/5)x + 1
By inspection of the equation, the slope of the line is -2/5 and the y-intercept is 1.
Therefore, we can immediately discount option B and D, as their y-intercepts are NOT 1.
Find the point where the line crosses the x-axis by setting the equation to 0 and solving for x:
0 = (-2/5)x + 1
⇒ -1 = (-2/5)x
⇒ -5 = -2x
⇒ x = 5/2
Therefore, the line of the function intersects the x-axis at x = 5/2 = 2.5
From inspection of the graphs, the line in option A intersects the x-axis at 2.5. Therefore, this is the correct graph.
Answer:
Time = 3secs
Max height = 56m
Step-by-step explanation:
Given the height reached by the rocket modeled by the equation;
h(x) = -5(x - 3)² + 56 where;
x is in seconds
The rocket velocity at its maximum height is zero.
Hence dh/dx = 0
dh/dx = 2(-5)(x-3)
dh/dx = -10(x-3)
Since dh/dx = 0
0 = -10(x-3)
0 = -10x + 30
10x = 30
x = 3secs
<em>Hence it takes 3 secs to reach the maximum height.</em>
Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;
Recall that:
h(x) = -5(x - 3)² + 56
If x = 3
h(3) = -5(3 - 3)² + 56
h(3) = 0 + 56
h(3) = 56
<em>Hence the maximum height that the rocket reaches is 56m</em>
3:18-1:33=188 so I think that’s ur answer
Answer:
v=3
u=6
x=2√2
y=2√2
Step-by-step explanation:
First triangle :
tanΦ=v/3√3
tan30=v/3√3
(√3)/3=v/(3√3)
Cross multiply
(√3)/3 x 3√3=v
(√3 x 3√3)/3=v
(3√9)/3=v
(3x3)/3=v
9/3=v
3=v
v=3
Sin30=v/u
0.5=3/u
Cross multiply
0.5xu=3
0.5u=3
Divide both sides by 0.5
0.5u/0.5=3/0.5
u=6
Second triangle :
sin45=x/4
Cross multiply
x=4 x sin45
x=4 x (√2)/2
x=2√2
Cos45=y/4
Cross multiply
4 x Cos45=y
4 x (√2)/2=y
(4√2)/2=y
2√2=y
y=2√2
