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3 years ago

Los numero de abajo siguen un patron 0.006, 0.06, 0.6, 6 cuales son los siguientes 2 numeros en el patron

Mathematics

1 answer:

a_sh-v [17]3 years ago

4 0

Answer:

6.00

Step-by-step explanation:

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Answer:

C- 29.25

Step-by-step explanation:

This answer goes into the thousendths place, meaning this is the most accurate.

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3 years ago

find three numbers whose sum is 32 if the second is 1 more than the first and the first is 4 less than the third

Alex777 [14]

X+y+z=32
x=z-4
y=x+1
z=x+4
x+x+1+x+4=32
3x+5=32
3x=27
x=9
y=10
z=13

Hope this helps :)

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3 years ago

In circle O, RV= 4 and VO= 7 find BA

Talja [164]

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3 years ago

C=Wtc/1000 for W please I need help it's algebra

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C1000÷ct=w

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3 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago