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Studentka2010 [4]
2 years ago
11

---8 (-5 + 13) + 12 : 6 x 2

Mathematics
1 answer:
madreJ [45]2 years ago
6 0

Step-by-step explanation:

-8 ( - 5 + 13) + 2 : 1 x 2

-8 ( 8) + 2 : 2

-64 + 1

-63

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If the circumference is 78.1 inches what is the diameter rounded to the nearest 10th
hammer [34]

Answer:

The diameter of the circle is 24.9 in

Step-by-step explanation:

To solve this exercise we need to use the circumference formula of a circle and clear d:

c = circumference = 78.1 in

d = diameter

π = 3.14

c = π * d

d = c / π

we replace the known values

d = 78.1 in / 3.14

d = 24.8726 in

round to the nearest tenth

d = 24.8726 in = 24.9 in

The diameter of the circle is 24.9 in

5 0
2 years ago
3 1/3 times 3 3/4 dived 5/6
Cloud [144]
I believe it is 0.41666666666 that what I got.
5 0
3 years ago
Read 2 more answers
A is true but f(x) is wrong need help
MrRissso [65]

Answer:

f(x)=-18x^2

Step-by-step explanation:

Given:

1+Integral(f(t)/t^6, t=a..x)=6x^-3

Let's get rid of integral by differentiating both sides.

Using fundamental of calculus and power rule(integration):

0+f(x)/x^6=-18x^-4

Additive Identity property applied:

f(x)/x^6=-18x^-4

Multiply both sides by x^6:

f(x)=-18x^-4×x^6

Power rule (exponents) applied"

f(x)=-18x^2

Check:

1+Integral(-18t^2/t^6, t=a..x)=6x^-3

1+Integral(-18t^-4, t=a..x)=6x^-3

1+(-18t^-3/-3, t=a..x)=6x^-3

1+(6t^-3, t=a..x)=6x^-3

That looks great since those powers are the same on both side after integration.

Plug in limits:

1+(6x^-3-6a^-3)=6x^-3

We need 1-6a^-3=0 so that the equation holds true for all x.

Subtract 1 on both sides:

-6a^-3=-1

Divide both sides by-6:

a^-3=1/6

Raise both sides to -1/3 power:

a=(1/6)^(-1/3)

Negative exponent just refers to reciprocal of our base:

a=6^(1/3)

3 0
2 years ago
What steps can you use to solve the equation 9 equals Y +4
kirill115 [55]

Answer:

See Below

Step-by-step explanation

1) subtract 4 from both sides

You have the answer

7 0
2 years ago
Someone help me pls!!!!!!!!<br> math problem
Liono4ka [1.6K]

Answer:

{1,6}

Step-by-step explanation:

the second box is always where the y values/range are

6 0
2 years ago
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