Use a graphing calculator to sketch the graph of the quadratic equation, and then give the coordinates for the x-

Jacob went camping with his family. At 7:15 A.M., Jacob set out to go fishing. It took 1 hour and 45 minutes to hike to the lake

GREYUIT [131]

Answer:

7:15 A.M.
1 hour and 45 min = 105 min
3 hour 45 min= 225 min
1 hour and 15 min = 105 min
105(2)+ 225= 435 min= 7 hours and 25 min.
Add that to the original total you get 14:40 P.M

7 0

3 years ago

M,n how much is it in math

Elena-2011 [213]

Answer:

you can't really determine how much letters equal if there is not an equation but it represents variables that stand for integers

Step-by-step explanation:

hope this helps have a good rest of your night :) ❤

4 0

3 years ago

Anyone knows how to do questions 7 and 8? 15 pts!!

Oksi-84 [34.3K]

7) Certainly there is a typo in the statement, just see that the expression of item (ii) is different from that of item (i). Probably the correct expression is: $2x^2-4x+5$ . With this consideration, we can continue.

(i) Let E the expression that we are analyzing:

$E=2x^2-4x+5\\\\ E=2x^2-4x+2-2+5\\\\ E=2(x^2-2x+1)-2+5\\\\ E=2(x-1)^2+3$

Since (x-1)² is a perfect square, it is a positive number. So, E is a result of a sum of two positive numbers, 2(x-1)² and 3. Hence, E is a positive number, too.

(ii) Manipulating the expression:

$2x^2+5=4x\\\\ 2x^2-4x+5=0$

So, it's the case when E=0. However, E is always a positive number. Then, there is no real number x that satisfies the expression.

8) Let E the expression that we want to calculate:

$E=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)+1\\\\ E-1=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)$

Multiplying by (2-1) in the both sides:

$(2-1)(E-1)=(2-1)(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2-1)(2+1)}_{2^2-1}(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2^2-1)(2^2+1)}_{2^4-1}(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ ...$ Repeating the process, we obtain: $...\\\\ E-1=(2^{32}-1)(2^{32}+1)\\\\ E-1=2^{64}-1\\\\ \boxed{E=2^{64}}$

3 0

4 years ago

Read 2 more answers

What type of association would you expect to see between the amount of fog in the sky and the distance that a pilot can see? A)

Blizzard [7]

We can make a conclusion that the more fog there is, the less distance the pilot can see. this means that there is a negative association because if this were graphed, the slop would be negative, as the x-axis (amount of fog) increases and the y-axis (distance pilot can see) decreases.

7 0

3 years ago

A digital rain gauge has an outdoor sensor that collects rainfall and transmits data to an indoor display. Assume you produced a

evablogger [386]

Answer:

a. A continuous graph

b. a straight line graph with a gentle positive slope

c. The graph consists of three straight lines attached end to end, with the first segment being an inclined positively sloped graph, the second segment is an horizontal line while the third segment is a gentle positively sloped straight line

Step-by-step explanation:

a. A continuous graph

Given that the rain gauge is a digital rain gauge, the values transmitted to the indoor display are those collected by the outdoor sensor, we have that the output to the transmitter can be any value within a possible and finite range of values, therefore the graph is continuous

b. Whereby it rained at a constant rate of 0.1 inch per hour over 24-hour period, we have;

i) Whereby the graph is the level of water in the rain gauge over a given period of time, the shape of the graph will be a straight line graph with a gentle positive slope of 0.1 the domain will be from 0 to 24 hours, while the range will be from 0 to 2.4 inches

c) i) Given that i) the rain falls at a constant rate of 0.1 inch per hour for 6 hours, and ii) over the next 6 hours it stops raining, after which iii) it rained 0.2 inch for the next 12 hours, we have;

i) In the first part The graph will be a straight line graph with a gentle positive slope of 0.1, up to the point (6, 0.6)

ii) When the rain stops for 6 hours, from the point (6, 0.6) to the point (12, 0.12) the graph will be an horizontal line

iii) From the point (12, 0.12) to the point (24, 0.24), is represented on the graph by a straight line with a gentle positive slope of 0.2.

7 0

3 years ago