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julia-pushkina [17]
2 years ago
6

Select the expression that has a value of 6.2,400 ÷ 402,400 ÷ 4240 ÷ 40240 ÷ 4

Mathematics
1 answer:
Svetlanka [38]2 years ago
8 0

Answer:

the value is 2.2721803393 x 1400

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\bf \measuredangle x=\cfrac{1}{2}(\widehat{AB}+\widehat{CD})\impliedby \textit{intersecting chords theorem}
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A train travels at a constant speed and has traveled 67. 5 miles in the last 1 1/2 hours. Which equation shows the proportion re
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Find the speed of the train:

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Please! Due soon
Ivenika [448]

Answer:So, the least squares regression equation is : y= mx+b ⇒ y= 6.33x +38.71

b. When x= 8, then y= (6.33×8)+38.71 = 50.64 + 38.71 =89.35

The approximate test score of a student who sleeps an average of 8 h a night is 89.35%

Step-by-step explanation:

hey someone else has already answered this!

a. To find the least squares regression equation for a group of (x,y) points:

Step 1: For each point(x,y), we need to calculate x² and xy first.

Step 2: Sum all x, y, x² and xy, which gives us Σx, Σy, Σx² and Σxy

Step 3: Calculate Slope m: m = (NΣxy − Σx Σy)/ N(Σx²) − (Σx)² , here N is the number of data.

Step 4: Calculate Intercept b: b = Σy − m(Σx)/ N

Step 5: Assemble the equation as y= mx+b

Here, we have ∑x = 120, ∑y= 1379, ∑x²= 919.5, ∑xy= 10466 and N= 16

So, m= (NΣxy − Σx Σy)/ N(Σx²) − (Σx)²

=

=

=  

= 6.33

and b = Σy − m(Σx)/ N

=

=

=

= 38.71

So, the least squares regression equation is : y= mx+b ⇒ y= 6.33x +38.71

b. When x= 8, then y= (6.33×8)+38.71 = 50.64 + 38.71 =89.35

The approximate test score of a student who sleeps an average of 8 h a night is 89.35%

EVERYTHING IS FROM sicista on brainly!

4 0
3 years ago
.4^3Grafting, the uniting of the stem of one plant with the stem or root of another, is widely used commercially to grow the ste
11111nata11111 [884]

Answer:

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

Step-by-step explanation:

To solve this question, we need to understand the binomial probability distribution and conditional probability.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: No failed grafts in the first seven

Event B: At least one fail in the next three.

Intersection of events A and B:

Since the probability of a graft failling is independent of other grafts, we have that:

P(A \cap B) = P(A)*P(B)

So

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{P(A)*P(B)}{P(A)} = P(B)

So we just have to find the probability of one fail in three trials.

Three trials means that n = 3.

The probability is

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.4)^{0}.(0.6)^{3} = 0.216

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.216 = 0.784

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

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