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givi [52]
2 years ago
6

Each side of a square is increasing at a rate of 5 cm/s. at what rate is the area of the square increasing when the area of the

square is 49 cm2? 70 cm2/s
Mathematics
1 answer:
topjm [15]2 years ago
3 0
<span>This problem is solved using the chain rule. the area of the square is f(t) and the length of the side is g(t) f(t)=g(t)^2 g'(t)=5 Using the chain rule f'(t)=2*g(t)*g'(t) The value of g(t) is sqrt(49) which is 7. g'(t) is given as 5 cm/s f'(t)=2*7*5=14*5=70cm^2/s</span>
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Find an equation for the nth term of the arithmetic sequence. -15, -6, 3, 12, ...
Mariulka [41]

Answer: t_{n}=-15+9(n-1)

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is given as:

t_{n}=a+(n-1)d

a = first term = -15

d = common difference = -6 - (-15) = 9

n = number of terms

substituting into the formula , we have :

t_{n} = -15+(n-1)9

t_{n}=-15+9(n-1)

5 0
2 years ago
Please help me on this I’m super stuck
erastova [34]

Answer:

<u>BC = 3.1666</u>

Step-by-step explanation:

To solve this you need to know that cosine∅ = adjacent/hypotenuse. We already know that hypotenuse = 5 and that ∅ = 70*. By substituting these in you will get cosine 70* = adjacent/5. Evaluate cosine 70* on the calculator and get 0.633... Multiply both sides by 5 and get adjacent is about equal to 3.1666. Because BC is the adjacent side of the triangle, this is the length of BC.

6 0
3 years ago
The area of a triangle is 150 square feet. If the base is 15 feet , calculate the height.
Evgen [1.6K]
The height would be 20 feet.
4 0
3 years ago
Read 2 more answers
What is the time and space margin that is the distance you can see ahead of your vehicle?
IgorLugansk [536]
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The time margin depends on the space margin, your reaction time, and your speed of travel.

You may appear to have a lot of time or space in icy conditions, but that can be an illusion. A collision course on ice will result in a collision, regardless of the time or distance involved.

Insufficient information is provided to be more specific.
5 0
3 years ago
Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF
drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD    and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

\therefore m\angle A = m\angle B ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

m\angle F=m\angle E=90\° ⇒2

Now In △ABE and △CBF

∠A = ∠C   (from 1)

∠E = ∠F    (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

7 0
3 years ago
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