Answer: https://prezi.com/p/wqgmakneo7_m/net-pay/
Step-by-step explanation: watch and youll get an answer
0.941176471 to the nearest hundredth is 0.94
Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,


which is a cubic polynomial in
with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,

where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then
can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)
The correct answer is D the very last one.
I think the greatest number less than 700 with 9 in the tens place and different digits in each of the other places is 698.
I chose 6 to be in the one of hundreds place because it is the greatest number that is less than 7 in the hundreds place. I also chose 8 to be in the ones place because it is different from 6 and 9 and the greatest number in the ones place that is not 9.