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Sever21 [200]
3 years ago
9

For a pyramid S.ABC of volume V. Let M be a point on side AB such that AM/AB = x. The plane (alpha) through M is parallel to two

straight lines SA, BC. the plane (alpha) divides the pyramid into 2 parts, in which the part containing the point B has a volume of V' with V' = 208/343V. The sum of the values ​​of x satisfies the problem.
A. 3/2 B.3/7 C.135/686 D.0
Mathematics
2 answers:
Doss [256]3 years ago
4 0

Answer:

Can't understand your question

kondaur [170]3 years ago
4 0

Answer:

Hi...Have a wonderful day...

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The sides of a right triangle are x, x+21, and x+27. what is the length of the hypotenuse
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The three numbers are x , x + 21 and x + 27. 
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Pythagoras Theorem
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a² + b²  = c²

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x = 24 or x = -12 (rejected, length cannot be negative)

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Find hypotenuse
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 Hypotenuse = x + 27 = 24 + 27 = 51 units

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Answer: 51 units
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