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Archy [21]
2 years ago
9

What is the solution to the equation 8r + 6 = 2?

Mathematics
2 answers:
topjm [15]2 years ago
8 0

Answer:

r = - \frac{1}{2}

Step-by-step explanation:

8r + 6 = 2 ( subtract 6 from both sides )

8r = - 4 ( divide both sides by 8 )

r = \frac{-4}{8} = - \frac{1}{2}

vitfil [10]2 years ago
5 0

Answer:

=−12

Step-by-step explanation:

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4 0
2 years ago
A garden supply store sells two types of lawn mowers. Total ales of mowers for the year were $8379.70. The total number of mower
Anestetic [448]

Answer:

The number of small mowers are 19 and the large mowers are 11.

Step-by-step explanation:

Given:

A garden supply store sells two types of lawn mowers. Total sales of mowers for the year were $8379.70. The total number of mowers sold the 30. The small mower cost $249.99 and the large mower costs $329.99.

Now, to find the number of each type of mower sold.

Let the number of small mower be x.

And the number of large mower be  y.

So, total number of mowers are:

x+y=30

x=30-y\ \ \ ....(1)

Now, the total sales of mowers are:

249.99(x)+329.99(y)=8379.70

Substituting the value of x from equation (1) we get:

249.99(30-y)+329.99y=8379.70

7499.7-249.99y+329.99y=8379.70

7499.7+80y=8379.70

<em>Subtracting both sides by 7499.7 we get:</em>

80y=880

<em>Dividing both sides by 80 we get:</em>

y=11.

The number of large mower = 11.

Now, to get the number of small mowers we substitute the value of y  in equation ( 1 ):

x=30-y\\x=30-11\\x=19.

The number of small mower = 19.

Therefore, the number of small mowers are 19 and the large mowers are 11.

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3 years ago
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Kisachek [45]

Oh the ani me? I know the an ime if that’s what your talking about lol if not then I have no clue

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3 years ago
(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf
alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

Total of scale usage is 2

b) if you have 3^n coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.

Step 1: you narrow down to group of \frac{3^n}{3} = 3^{n-1} coins

Step 2: you narrow down to group of \frac{3^{n-1}}{3} = 3^{n-2} coins

Step 3: you narrow down to group of \frac{3^{n-2}}{3} = 3^{n-3} coins

...

Step n: Step 1: you narrow down to group of 3^{n-n} = 3^0 = 1coin

8 0
3 years ago
Is 2/1 x 1/2 greater than 1/2
Mariulka [41]
Yes it is greater than 1/2
6 0
3 years ago
Read 2 more answers
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