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2 years ago

I really dont get what math is

Mathematics

2 answers:

gtnhenbr [62]2 years ago

8 0

Answer:

the abstract science of number, quantity, and space. Mathematics may be studied in its own right ( pure mathematics ), or as it is applied to other disciplines such as physics and engineering ( applied mathematics ).

Step-by-step explanation:

laiz [17]2 years ago

3 0

math is a subject that was made to ... umm... torture kids & make them mentally depressed!! kidding...so NOT!

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I NEED HELP...finding the slope-intercept form equation

Simora [160]

Answer: y=-13/12x-7

Step-by-step explanation:

To find the slope-intercept form, we first need to find the slope. To find the slope, you use the formula $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ . We use the two given points to find the slope.

$m=\frac{32-6}{-36-(-12)} =\frac{26}{-24} =-\frac{13}{12}$

Now that we have our slope, we can start filling out the slope-intercept form equation.

y=mx+b

y=-13/12x+b

Since we don't know the y-intercept, we can use one of the given points and solve for b.

6=(-13/12)(-12)+b [multiply (-13/12) and -12]

6=13+b [subtract both sides by 13]

b=-7

With the y-intercept, we can complete our equation.

y=-13/12x-7

4 0

2 years ago

I need help plzz!! Just box number 4, TY

nydimaria [60]

12.36% I think sorry if its wrong ;-;

3 0

2 years ago

a set of angels has a ratio of 5:2 . If the larger angle measures 105 degrees then what is the measure of the smaller angle

Igoryamba

Answer:

Step-by-step explanation:

6 0

3 years ago

There is a proportinal relationship between the volume of a sample of helium in liters and the mass of that sample in grams. if

Oksanka [162]

Answer:

im trying to figure out the same question

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

show that the equation 3x2 + 3y2 + 6x-y= 0 represents a circle and find the centre and radius of the circle

Jlenok [28]

Answer:

Center of the circle: $(-1,\frac{1}{6})$

Radius of the circle: $\frac{\sqrt{37} }{6}$

Step-by-step explanation:

Let's start by dividing both sides of the equation by the factor "3" so we simplify our next step of completing squares for x and for y:

$3x^2+3y^2+6x-y=0\\x^2+y^2+2x-\frac{1}{3} y=0$

Now we work on completing the squares for the expression on x and for the expression on y separately, so we group together the terms in "x" and then the terms in "y":

$x^2+y^2+2x-\frac{1}{3} y=0\\( x^2+2x ) + (y^2-\frac{1}{3} y)=0$

Let's find what number we need to add to both sides of the equation to complete the square of the group on the variable "x":

$( x^2+2x ) = 0\\x^2+2x+1=1\\(x+1)^2=1$

So, we need to add "1" to both sides in order to complete the square in "x".

Now let's work on a similar fashion to find what number we need to add on both sides to complete the square for the group on y":

$(y^2-\frac{1}{3} y)=0\\y^2-\frac{1}{3} y+\frac{1}{36} =\frac{1}{36}\\(y-\frac{1}{6} )^2=\frac{1}{36}$

Therefore, we need to add " $\frac{1}{36}$ " to both sides to complete the square for the y-variable.

This means we need to add a total of $1 + \frac{1}{36} = \frac{37}{36}$ to both sides of the initial equation in order to complete the square for both variables:

$x^2+y^2+2x-\frac{1}{3} y=0\\x^2+y^2+2x-\frac{1}{3} y+\frac{37}{36} =\frac{37}{36} \\(x+1)^2+(y-\frac{1}{6} )^2=\frac{37}{36}$

Now recall that the right hand side of this expression for the equation of a circle contains the square of the circle's radius, based on the general form for the equation of a circle of center $(x_0,y_0)$ and radius R:

$(x-x_0)^2+(y-y_0)^2=R^2$

So our equation that can be written as:

$(x+1)^2+(y-\frac{1}{6} )^2=(\sqrt{\frac{37}{36}} )^2$

corresponds to a circle centered at $(-1,\frac{1}{6})$ , and with radius $\sqrt{\frac{37}{36}}=\frac{\sqrt{37} }{6}$

5 0

2 years ago