The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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what is the maximum, minimum, quartile 1, median, quartile 3, range, interquartlie range of these numbers " 46,48,50,52, and 54"
Gekata [30.6K]
Min=46
Max=54
1 quartile= 48
Median=50
3 quartile=52
46/48 percent is 95.83%
Answer:
is correct
Step-by-step explanation:
Answer: x=49
Step by step explanation: to find one of the sides just subtract 35 from 60, then you get 35/25=x/35, which is 25x=1225, the last step is to divide both sides by 25 and you get the final result of 49
Answer:
cost per pound = $4.20
Step-by-step explanation:
Cheese cost per pound = ?
first for the cost per pound
cost per pound = total cost / pounds bought
cost per pound = $10.50 / 2.5 pounds
cost per pound = $4.20
to check the above answer is correct
cost per pound = total cost / pounds bought
cost per pound = $12.60 / 3 pounds
cost per pound = $4.20
Therefor, the cheese costs $4.20 per pound.
