Answer:
Total DRAM memory = 1.6 * 8 * 10^9 Bytes J/seconds = 12.8*10^9 J/s ---1
Total energy required to read or write cache-line to Flash and DRAM = 2*64*( 2.56 *10^-6+0.5 *10^-9) J = 3.277*10^-4 J---2
The time a system will be idle is 2/1 = 2.56*10^-14 seconds
Explanation:
Here, the 2 and 1 in the last step corresponds to the answers from equation equation 1 and equation 2.
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Answer:
do u have different networks too?
Profile let's go with profile hope this helps
Answer:
ask your teacher ok boy☺️☺️☺️
