The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
X+y=6
x=10
10+y=6
y=-4
10=-4+z
-4+z=10
z=10+4
z=14
So the correct answer is 14
Answer:
f(-3) = 9
Step-by-step explanation:
Step 1: Define
f(-3) = x = -3
f(x) = x²
Step 2: Substitute and Evaluate
f(-3) = (-3)²
f(-3) = 9
Answer:
J 8.5 >=2.5p
Step-by-step explanation:
To do this plug in 3.4 for each version of p. The only one that would be true would be J.
Answer:
hour
Step-by-step explanation:
Let x represent time taken by dog to run the 1 and three tenths -mile state fair race.
We have been given that a dog won a race at the local fair by running 3 and one fourth miles in exactly 2 hours.
We will use proportions to solve our given problem as:
We will equate both speeds as:
Cross multiply:
Therefore, it will take hour to complete 
mile state fair race.
