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zmey [24]
3 years ago
5

Can someone help me please :))?

Mathematics
1 answer:
Maslowich3 years ago
3 0

Answer:

The total cost depends on the weight of the package

Step-by-step explanation:

When looking at a graph, know that the x-axis is the independent variable. It can change, but is independent of other factors.

The y-axis is the dependent variable, which changes based on the independent variable.

You might be interested in
In the interval 0° < x < 360°, find the values of x for which sin x = 0.6691 Give your answer tot he nearest degree
Neporo4naja [7]

Answer:

x are 42 and 138degees

Step-by-step explanation:

Given the expression  sin x = 0.6691

sin x = 0.6691

Take the sin inverse of both sides

sin⁻¹(sin x) =  sin⁻¹(0.6691 )

x = sin⁻¹(0.6691 )

x = 41.99

x = 42 degrees (to the nearest degree)

Since sin theta is positive in the second quadrant;

x = 180 -theta

x = 180 - 42

x = 138degrees

Hence the value of x are 42 and 138degees

8 0
3 years ago
2y - 7+ 5y = 0<br> Step by step work
Ugo [173]

Answer:

y=1

Step-by-step explanation:

2y+5y-7=0

Combine y: 7y-7=0

Move 7 over: 7y=7

Divide by 7:y=1

5 0
3 years ago
Amar and his friends went to a movie at 3:55 P.M. The movie ended at 5:30 P.M.
kotegsom [21]

Answer: the movie was 1 hour and 35 minutes and Amar got home at 6:15 P.M.

Step-by-step explanation:

to find out how long the movie was you have to find the distance between the time frames 3:55 and 5:30.

3:55+1 hour= 4:55

4:55+5 minutes= 5:00

5:00+30 minutes= 5:30

Add the times to find how long the movie was.

This is how I found how long the movie was.

To find out when Amar got home you have to do the same thing as well.

5:30+30 minutes= 6:00

6:00+15 minutes= 6:15

Hope this helps!

6 0
3 years ago
The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
3 years ago
Question 1 of 10
Naddika [18.5K]

Answer:

B. 6x2+x+7

Step-by-step explanation:

combine like terms

3x^2+3x^2= <u>6x^2</u>

<u>x</u>

3+4=<u>7</u>

3 0
3 years ago
Read 2 more answers
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