Answer:
The girl is doing work on the ball because the energy in her muscles changed, even though the ball is not displaced.
Explanation:
The complete question is...
Which of these correctly describes whether a girl holding a ball in the same position is doing work on the ball?
-The girl is doing work on the ball because the energy of the ball changed, even though it is not displaced.
-The girl is doing work on the ball because the energy in her muscles changed, even though the ball is not displaced.
-The girl is doing no work on the ball because the ball is not displaced.
-The girl is doing no work on the ball because she is exerting a net force on the ball.
Holding up a ball costs energy, which is used to counter the work that would have otherwise be done on the ball by gravity. Although no physical distance is moved, we should consider the fact that by holding the ball, the girls hand exerts physical force to hold the ball in place. Also, there is a potential gravitational work on the ball due to gravity, but the force exerted by the girls hand does an equivalent of this gravito-potential work in order to counter it and hold the ball in place. All these activities eventually lead to a change in energy in her hand muscle to show that energy is expended.
Answer:
Explanation:
Initial speed, v = 10 x 10^3 m/s
Mass of the earth, M = 6 x 10^24 kg
Radius of the earth, R = 6.4 x 10^6 m
Maximum from the surface of earth, h = ?
Let m = Mass of the projectile
Solution:
Potential energy at maximum height = ( Potential + Kinetic energy ) at the surface
![-G M m / ( R + h )=- G M m / R + (1/2) m v^2](https://tex.z-dn.net/?f=-G%20M%20m%20%2F%20%28%20R%20%2B%20h%20%29%3D-%20G%20M%20m%20%2F%20R%20%2B%20%281%2F2%29%20m%20v%5E2)
![- G M / ( R + h ) = - G M / R + (1/2) v^2](https://tex.z-dn.net/?f=-%20G%20M%20%2F%20%28%20R%20%2B%20h%20%29%20%3D%20-%20G%20M%20%2F%20R%20%2B%20%281%2F2%29%20v%5E2)
![-2\times G M / ( R + h ) = ( - 2 G M / R ) + v^2](https://tex.z-dn.net/?f=-2%5Ctimes%20G%20M%20%2F%20%28%20R%20%2B%20h%20%29%20%3D%20%28%20-%202%20G%20M%20%2F%20R%20%29%20%2B%20v%5E2)
=![( (- 2\times 6.67\times10^{-11}\times6\times10^{24}) /(6.4\times10^6)} +10000^2](https://tex.z-dn.net/?f=%28%20%28-%202%5Ctimes%206.67%5Ctimes10%5E%7B-11%7D%5Ctimes6%5Ctimes10%5E%7B24%7D%29%20%2F%286.4%5Ctimes10%5E6%29%7D%20%2B10000%5E2)
=![-2.50625\times10^7 J](https://tex.z-dn.net/?f=-2.50625%5Ctimes10%5E7%20J)
![=- 8\times10^{14} / ( R + h )=-2.50625\times 10^7](https://tex.z-dn.net/?f=%3D-%208%5Ctimes10%5E%7B14%7D%20%2F%20%28%20R%20%2B%20h%20%29%3D-2.50625%5Ctimes%2010%5E7)
![R+h=31.92\times10^{6}](https://tex.z-dn.net/?f=R%2Bh%3D31.92%5Ctimes10%5E%7B6%7D)
![h=31.92\times10^{6}-6.4\times10^6](https://tex.z-dn.net/?f=h%3D31.92%5Ctimes10%5E%7B6%7D-6.4%5Ctimes10%5E6)
Answer:
v = 3.00 x 10⁸ m/s
Explanation:
given,
speed of light in vacuum = 299,792,458 m/s
speed of light in scientific notation to three significant figures
v = 2.99792458 x 10⁸ m/s
by rounding off the speed to three significant figure.
v = 3.00 x 10⁸ m/s
On the fourth place the value is greater than 5 so, on the third place 1 will be added.
now, the speed with three significant figure comes out to be
v = 3.00 x 10⁸ m/s
Answer:
Columns of the periodic table are called groups.