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Ne4ueva [31]
3 years ago
5

A small car collides with a large truck is the magnitude of the force experience by the car greater than less than or equal to t

he magnitude of the force experience by the truck
Physics
2 answers:
kodGreya [7K]3 years ago
6 0
Less than because the car is lighter and less forceful than the large truck
Likurg_2 [28]3 years ago
3 0
The magnitude of the force experienced by the car would be less; force equals mass times acceleration (F=ma) the car would have significantly less mass, making the force less.
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Neon has 10 protons and 10 electrons. How many additional electrons would it take to fill the outer (second) electron shell?
Yakvenalex [24]
None because Neon is already stable
8 0
3 years ago
Naomi is taking a train from DC to New York which is 360km apart. If the train is traveling at an average speed of 32 meters per
rodikova [14]

Answer:

11250 seconds or 187.5 mins

Explanation:

The formula to be used here is that of speed.

Speed (in m/s) = distance (meter) ÷ time (secs)

The speed provided is 32 meters per second

The distance provided will have to be converted to meters; 360 km = 360 × 1000 = 360000 meters

Thus,

32 = 360000 ÷ time

time = 360000 ÷ 32

time = 11250 seconds or 187.5 mins

It will take Naomi 11250 seconds to get to New York

4 0
3 years ago
Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012 W) pu
ASHA 777 [7]

Answer:

the best way to prevent cancer is to eat right

Explanation:

4 0
3 years ago
Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very
timofeeve [1]

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ v=\frac{502.1}{\sqrt{3} }

      =289.9 \ m/s

The time will be:

⇒ t=\frac{d}{v}

      =\frac{2\times 6}{289.9}

      =\frac{12}{289.9}

      =0.041 \ sec

hence,

⇒ N=\frac{1}{t}

        =\frac{1}{0.041}

        =24.39 \ per \ sec

4 0
3 years ago
A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coas
Pavel [41]

Complete question is:

A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 m/s. Neglect friction.

Answer:

(V_A) = 31.32 m/s

Explanation:

We are given;

car's mass, m = 1200 kg

h_A = 100 m

h_B = 150 m

v_B = 0 m/s

From law of conservation of energy,

the distance from point A to B is;

h = 150m - 100 m = 50 m

From Newton's equations of motion;

v² = u² + 2gh

Thus;

(V_B)² = (V_A)² + (-2gh)

(negative next to g because it's going against gravity)

Thus;

(V_B)² = (V_A)² - (2gh)

Plugging in the relevant values;

0² = (V_A)² - 2(9.81 × 50)

(V_A) = √981

(V_A) = 31.32 m/s

3 0
3 years ago
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