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3 years ago

The quotient of ninety five and a number is what

Mathematics

1 answer:

djyliett [7]3 years ago

8 0

This is how you solve it..
95/n=n
You could put 5 in and get 95/5=19.

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Evaluate h(x) = -2x + 9 when x = -2.0. and 5

Len [333]

Answer:

h(-2) = 13

h(5) = -1

Step-by-step explanation:

Given the function

h(x) = -2x + 9

Evaluating at x = -22

substitute x = -2

h(-2) = -2(-2) + 9

h(-2) = 4 + 9

h(-2) = 13

Therefore,

h(-2) = 13

Evaluating at x = 5

Given the function

h(x) = -2x + 9

substitute x = 5

h(5) = -2(5) + 9

h(5) = -10 + 9

h(5) = -1

Therefore,

h(5) = -1

4 0

3 years ago

(b) if the length, width, and height are increasing at a rate of 0.1 ft/sec, 0.2 ft/sec, and 0.5 ft/sec respectively, find the r

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4 years ago

Read 2 more answers

) Esteban tiene cerámicas

Ad libitum [116K]

Answer:

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Step-by-step explanation:

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3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago

Hello today is my birthday please help !!

scoray [572]

Answer:

the last one(y=2(2/3)^x) is the correct answer

Step-by-step explanation:

I identify two coordinate on the graph (0,2) and (1,3) and I noticed only the last one gives you a appropriate output if you plug the correspond input value

4 0

2 years ago