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Zina [86]
3 years ago
9

8^x=2 write down the value of x

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

x = \frac{1}{3}

Step-by-step explanation:

Using the rule of exponents

a^m^{n} = a^{mn}

Note that 8 = 2³ and 2 = 2^{1}, then

(2^3)^{x} = 2^{1}, that is

2^{3x} = 2^{1}

Since the bases on both sides are equal, equate the exponents

3x = 1 ( divide both sides by 3 )

x = \frac{1}{3}

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that answer your question?

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3 years ago
The product of 6g2 and -2g3 is equals to​
ryzh [129]

Answer:

We conclude that:

\left(6g^2\:\right)\times \left(-2g^3\right)=-12g^5            

Step-by-step explanation:

Given

  • 6g²
  • -2g³

The product of 6g² and -2g³ can be determined by multiplying each other such as:

(6g^2\:)\times \:(-2g^3)

Apply the rule:  a(-b) = -ab

\left(6g^2\:\right)\times \left(-2g^3\right)=-6g^2\times \:\:2g^3

Apply exponent rule:   a^b\times \:a^c=a^{b+c}

                          =-6g^{2+3}\times \:2

                          =-6g^5\times \:2

                          =-12g^5

Therefore, we conclude that:

\left(6g^2\:\right)\times \left(-2g^3\right)=-12g^5            

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