Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Substitute the value of x in equation 2. Then you'll get y=3. Then again substitute the value of y in x=1+y, you'll get x=4
Answer:
a: vertical stretch
h: horizontal translation (remember not to get signs mixed up!)
k: vertical translation
5x+1(6-4) = +1(5x6)-(5x)
this would be a hard question to answer but i think i can do it ((( nNOTTTT))))
