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algol [13]
2 years ago
7

what is the length of the diagonal of a rectangle with width 3,5 cm and length 4,5 cm give your answer in simplest surd form​

Mathematics
1 answer:
atroni [7]2 years ago
4 0

Answer:

Step-by-step explanation:

By Pythagoras:

d^2 = (3.5)^2 + (4.5)^2

d^2 = 12.25 + 20.25 = 32.5

d = √32.5

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The circumference of a circle exceeds the radius by 74 cm. Find the radius of the circle.​
saw5 [17]

Answer:

14 cm.

Step-by-step explanation:

Let the radius of the circle = r cm.

Then circumference of circle = 2 π r.

Since circumference exceeds the radius by 74 cm

Therefore, according to the question,

\sf \:2 π r = r+ 74

\sf \: =   > 2 \times  \frac{22}{7}  \times r =  r \:  + 74

\sf \: =  >  \frac{44r}{7}  -r  = 74

\sf \:  =  > \frac{44r - 7r}{7}  = 74

\sf \: =  >  \frac{37r}{7}  = 74

\sf \: =  > r =  \frac{7 \times 74}{37}

\sf \: =  >  r = 14

  • Hence, the radius of the circle is 14 cm.

________________________________

3 0
2 years ago
Read 2 more answers
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
A firm has the following fixed proportion production function q = min(k, 2l). a. Find the firms long-run total, average, and mar
Yuri [45]

Answer:

I think its right

Step-by-step explanation:

a) In the long run, we have, 5k=10 and k=2l Thus, C=2l+3l= 5l=0.5q Thus, AC=5l/10l =0.5 MC=0.5 b) In the short run, k=10 Q=min(50,10l) If l<5, q=10l. C=10+3l= 10+0.3q Thus, AC=10/q + 0.3 If l>5, q=50. C= 10+3l AC= (10+3l)/50 If q>50, then MC...

3 0
2 years ago
My brain capacity can not handle this one right now? Anyone good with geometry word problems? It’s number 12 if anyone is able t
densk [106]

Check the picture below.

8 0
4 years ago
Which of the following statements are true of the graph of the function f(x)=(x+5)(x-3)?
mr_godi [17]

Answers: b, d and e

b.The graph has a relative minimum

d. The graph has an x intercept at 3,0

e. the graph has an y intercept at 0,-15

f(x)=(x+5)(x-3)

The given equation is in the form of f(x) = a(x-b)(x-c)

If 'a' is positive then graph has a relative minimum

If 'a' is negative then graph has a relative maximum

Here a=1 that is positive so graph has a relative minimum .

To find x intercept we set f(x) =0 and solve for x

0=(x+5)(x-3)

x+5 =0 -> x = -5 so x intercept is (-5,0)

x - 3=0 -> x= 3 so x intercept is (3,0)

To find y intercept we plug in 0 for x

y=(x+5)(x-3)

y=(0+5)(0-3) = -15

so y intercept is (0,-15)



5 0
3 years ago
Read 2 more answers
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