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zvonat [6]
3 years ago
7

A line passes through the points (3,21) and (8,26) Write a linear function rule in terms of x and y for this line.

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

y = x+18

Step-by-step explanation:

I'm not too sure about the terminology but I hope this helps!

In order to find the equation of any line, one can use the equation

<h3>m (gradient) = (y1 – y2 ) ÷ (x1 – x2)</h3>

(3,21) is the first named point; therefore, 3=x1 and 21=y1

Following the same logic, for the second point, 8=x2 and 26=y2.

Next, substitute these values into the equation above:

m = (21-26)÷(3-8)

m = -5/-5 = 1

Therefore, the gradient of this line is 1. So far our y=mx+c line equation has this information:

y=1x+c

Plugging in x and y values gives the y intercept (c):

21=3+c    (the values from point (8,26) can also be used here)

c = 18

Therefore, the line equation is y = x + 18

As a function, this could be f(x) = x + 18 (although I'm not too sure about this part!)

I hope this helped.

<h3 /><h3 />
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<u>Quadratic Equation</u>

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