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3 years ago

I uploaded the answer to a file hosting below

Mathematics

1 answer:

lutik1710 [3]3 years ago

3 0

Answer:

C. is awnser

Step-by-step explanation:

Can I have brainliest * if wrong then D

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Need help with question 5) & 6)<br> TIA☺️

mart [117]

Answer:

1. a

2.d

3.b

4.e

5.c

Step-by-step explanation:

can't do question 6 though, sorry about that

7 0

3 years ago

To rent a bounce house: At Mike's Bounce Shop costs $30 plus $2 per hour. At Jose's Bounce Rentals, it costs $12 plus $8 per hou

ANEK [815]

Answer: After 3 hours both will have the same cost.

Step-by-step explanation:

Let x = Number of hours and y be the total cost.

Total cost = Initial cost + (cost per hour)(Number of hours)

At Mike's Bounce Shop,

Total cost (y)= 30+2x

At Jose's Bounce Rentals,

Total cost(y) = 12+8x

When both shops have the same cost, then

$12+8x=30+2x\\\\\Rightarrow\ 8x-2x=30-12\\\\\Rightarrow\ 6x=18\\\\\Rightarrow\ x=3$

Total cost = 12+8(3)=12+24=$36

Hence, After 3 hours both will have the same cost.

3 0

3 years ago

How to subtract 600,200 to 239,000

Mama L [17]

23900-600200= -361200

3 0

3 years ago

102 + 7y = 16<br> 15x + 8y 29<br> Is this consistent or inconsistent

mel-nik [20]

Answer:

Step-by-step explanation:

18y

6 0

3 years ago

Read 2 more answers

For 0 ≤ θ < 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)

gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0 or 1 - cos(θ) = 0

cos(θ) = 0 or cos(θ) = 1

[θ = arccos(0) + 2nπ or θ = -arccos(0) + 2nπ]

… or [θ = arccos(1) + 2nπ or θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ or θ = -π/2 + 2nπ] or [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0 ⇒ θ = π/2

• second solution set with n = 1 ⇒ θ = 3π/2

• third solution set with n = 0 ⇒ θ = 0

So, the first choice is correct.

6 0

3 years ago