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OleMash [197]
3 years ago
7

Customers can pick their own apples at well orchards. They pay $6 to enter the orchard and $2 per pound for the apples they pick

. Write a equation to model the total cost, y, for x pounds of apples.
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0
Y=6+2x

Since y equals the total cost, it will be on its own in the equation. 6 dollars is a set amount, meaning that no matter how many apples they pick it’ll stay the same. HOWEVER, the cost will change depending on how many pound of apples they get

Every pound of apples is equal to 2 dollars, and since x stands for pounds of apples, it’ll be ( ex: x = 2, so 2x = 2(2) = 4)

So the equation will be y = 6 + 2x

I hope this helps
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3.14*4*100=1256

I hope this helped

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-18p^{5} -30p^{4} +6p^{3}

Step-by-step explanation:

(-6p^{3} )(3p^2+5p-1)

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Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

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Help me and i will mark you the brainlyist
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1a. n ≤ 21
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